3.77 \(\int x \sqrt {\sinh ^{-1}(a x)} \, dx\)

Optimal. Leaf size=93 \[ -\frac {\sqrt {\frac {\pi }{2}} \text {erf}\left (\sqrt {2} \sqrt {\sinh ^{-1}(a x)}\right )}{16 a^2}-\frac {\sqrt {\frac {\pi }{2}} \text {erfi}\left (\sqrt {2} \sqrt {\sinh ^{-1}(a x)}\right )}{16 a^2}+\frac {\sqrt {\sinh ^{-1}(a x)}}{4 a^2}+\frac {1}{2} x^2 \sqrt {\sinh ^{-1}(a x)} \]

[Out]

-1/32*erf(2^(1/2)*arcsinh(a*x)^(1/2))*2^(1/2)*Pi^(1/2)/a^2-1/32*erfi(2^(1/2)*arcsinh(a*x)^(1/2))*2^(1/2)*Pi^(1
/2)/a^2+1/4*arcsinh(a*x)^(1/2)/a^2+1/2*x^2*arcsinh(a*x)^(1/2)

________________________________________________________________________________________

Rubi [A]  time = 0.19, antiderivative size = 93, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 7, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.700, Rules used = {5663, 5779, 3312, 3307, 2180, 2204, 2205} \[ -\frac {\sqrt {\frac {\pi }{2}} \text {Erf}\left (\sqrt {2} \sqrt {\sinh ^{-1}(a x)}\right )}{16 a^2}-\frac {\sqrt {\frac {\pi }{2}} \text {Erfi}\left (\sqrt {2} \sqrt {\sinh ^{-1}(a x)}\right )}{16 a^2}+\frac {\sqrt {\sinh ^{-1}(a x)}}{4 a^2}+\frac {1}{2} x^2 \sqrt {\sinh ^{-1}(a x)} \]

Antiderivative was successfully verified.

[In]

Int[x*Sqrt[ArcSinh[a*x]],x]

[Out]

Sqrt[ArcSinh[a*x]]/(4*a^2) + (x^2*Sqrt[ArcSinh[a*x]])/2 - (Sqrt[Pi/2]*Erf[Sqrt[2]*Sqrt[ArcSinh[a*x]]])/(16*a^2
) - (Sqrt[Pi/2]*Erfi[Sqrt[2]*Sqrt[ArcSinh[a*x]]])/(16*a^2)

Rule 2180

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[2/d, Subst[Int[F^(g*(e - (c*
f)/d) + (f*g*x^2)/d), x], x, Sqrt[c + d*x]], x] /; FreeQ[{F, c, d, e, f, g}, x] &&  !$UseGamma === True

Rule 2204

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[(F^a*Sqrt[Pi]*Erfi[(c + d*x)*Rt[b*Log[F], 2
]])/(2*d*Rt[b*Log[F], 2]), x] /; FreeQ[{F, a, b, c, d}, x] && PosQ[b]

Rule 2205

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[(F^a*Sqrt[Pi]*Erf[(c + d*x)*Rt[-(b*Log[F]),
2]])/(2*d*Rt[-(b*Log[F]), 2]), x] /; FreeQ[{F, a, b, c, d}, x] && NegQ[b]

Rule 3307

Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + Pi*(k_.) + (f_.)*(x_)], x_Symbol] :> Dist[I/2, Int[(c + d*x)^m/(E^(
I*k*Pi)*E^(I*(e + f*x))), x], x] - Dist[I/2, Int[(c + d*x)^m*E^(I*k*Pi)*E^(I*(e + f*x)), x], x] /; FreeQ[{c, d
, e, f, m}, x] && IntegerQ[2*k]

Rule 3312

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sin
[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1])
)

Rule 5663

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[(x^(m + 1)*(a + b*ArcSinh[c*x])^n)/
(m + 1), x] - Dist[(b*c*n)/(m + 1), Int[(x^(m + 1)*(a + b*ArcSinh[c*x])^(n - 1))/Sqrt[1 + c^2*x^2], x], x] /;
FreeQ[{a, b, c}, x] && IGtQ[m, 0] && GtQ[n, 0]

Rule 5779

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*(x_)^(m_.)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[d^p/c^
(m + 1), Subst[Int[(a + b*x)^n*Sinh[x]^m*Cosh[x]^(2*p + 1), x], x, ArcSinh[c*x]], x] /; FreeQ[{a, b, c, d, e,
n}, x] && EqQ[e, c^2*d] && IntegerQ[2*p] && GtQ[p, -1] && IGtQ[m, 0] && (IntegerQ[p] || GtQ[d, 0])

Rubi steps

\begin {align*} \int x \sqrt {\sinh ^{-1}(a x)} \, dx &=\frac {1}{2} x^2 \sqrt {\sinh ^{-1}(a x)}-\frac {1}{4} a \int \frac {x^2}{\sqrt {1+a^2 x^2} \sqrt {\sinh ^{-1}(a x)}} \, dx\\ &=\frac {1}{2} x^2 \sqrt {\sinh ^{-1}(a x)}-\frac {\operatorname {Subst}\left (\int \frac {\sinh ^2(x)}{\sqrt {x}} \, dx,x,\sinh ^{-1}(a x)\right )}{4 a^2}\\ &=\frac {1}{2} x^2 \sqrt {\sinh ^{-1}(a x)}+\frac {\operatorname {Subst}\left (\int \left (\frac {1}{2 \sqrt {x}}-\frac {\cosh (2 x)}{2 \sqrt {x}}\right ) \, dx,x,\sinh ^{-1}(a x)\right )}{4 a^2}\\ &=\frac {\sqrt {\sinh ^{-1}(a x)}}{4 a^2}+\frac {1}{2} x^2 \sqrt {\sinh ^{-1}(a x)}-\frac {\operatorname {Subst}\left (\int \frac {\cosh (2 x)}{\sqrt {x}} \, dx,x,\sinh ^{-1}(a x)\right )}{8 a^2}\\ &=\frac {\sqrt {\sinh ^{-1}(a x)}}{4 a^2}+\frac {1}{2} x^2 \sqrt {\sinh ^{-1}(a x)}-\frac {\operatorname {Subst}\left (\int \frac {e^{-2 x}}{\sqrt {x}} \, dx,x,\sinh ^{-1}(a x)\right )}{16 a^2}-\frac {\operatorname {Subst}\left (\int \frac {e^{2 x}}{\sqrt {x}} \, dx,x,\sinh ^{-1}(a x)\right )}{16 a^2}\\ &=\frac {\sqrt {\sinh ^{-1}(a x)}}{4 a^2}+\frac {1}{2} x^2 \sqrt {\sinh ^{-1}(a x)}-\frac {\operatorname {Subst}\left (\int e^{-2 x^2} \, dx,x,\sqrt {\sinh ^{-1}(a x)}\right )}{8 a^2}-\frac {\operatorname {Subst}\left (\int e^{2 x^2} \, dx,x,\sqrt {\sinh ^{-1}(a x)}\right )}{8 a^2}\\ &=\frac {\sqrt {\sinh ^{-1}(a x)}}{4 a^2}+\frac {1}{2} x^2 \sqrt {\sinh ^{-1}(a x)}-\frac {\sqrt {\frac {\pi }{2}} \text {erf}\left (\sqrt {2} \sqrt {\sinh ^{-1}(a x)}\right )}{16 a^2}-\frac {\sqrt {\frac {\pi }{2}} \text {erfi}\left (\sqrt {2} \sqrt {\sinh ^{-1}(a x)}\right )}{16 a^2}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.04, size = 52, normalized size = 0.56 \[ \frac {\frac {\sqrt {\sinh ^{-1}(a x)} \Gamma \left (\frac {3}{2},-2 \sinh ^{-1}(a x)\right )}{\sqrt {-\sinh ^{-1}(a x)}}+\Gamma \left (\frac {3}{2},2 \sinh ^{-1}(a x)\right )}{8 \sqrt {2} a^2} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[x*Sqrt[ArcSinh[a*x]],x]

[Out]

((Sqrt[ArcSinh[a*x]]*Gamma[3/2, -2*ArcSinh[a*x]])/Sqrt[-ArcSinh[a*x]] + Gamma[3/2, 2*ArcSinh[a*x]])/(8*Sqrt[2]
*a^2)

________________________________________________________________________________________

fricas [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*arcsinh(a*x)^(1/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (co
nstant residues)

________________________________________________________________________________________

giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x \sqrt {\operatorname {arsinh}\left (a x\right )}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*arcsinh(a*x)^(1/2),x, algorithm="giac")

[Out]

integrate(x*sqrt(arcsinh(a*x)), x)

________________________________________________________________________________________

maple [A]  time = 0.30, size = 75, normalized size = 0.81 \[ \frac {\sqrt {2}\, \left (8 \sqrt {2}\, \sqrt {\arcsinh \left (a x \right )}\, \sqrt {\pi }\, x^{2} a^{2}+4 \sqrt {2}\, \sqrt {\arcsinh \left (a x \right )}\, \sqrt {\pi }-\pi \erf \left (\sqrt {2}\, \sqrt {\arcsinh \left (a x \right )}\right )-\pi \erfi \left (\sqrt {2}\, \sqrt {\arcsinh \left (a x \right )}\right )\right )}{32 \sqrt {\pi }\, a^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*arcsinh(a*x)^(1/2),x)

[Out]

1/32*2^(1/2)*(8*2^(1/2)*arcsinh(a*x)^(1/2)*Pi^(1/2)*x^2*a^2+4*2^(1/2)*arcsinh(a*x)^(1/2)*Pi^(1/2)-Pi*erf(2^(1/
2)*arcsinh(a*x)^(1/2))-Pi*erfi(2^(1/2)*arcsinh(a*x)^(1/2)))/Pi^(1/2)/a^2

________________________________________________________________________________________

maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x \sqrt {\operatorname {arsinh}\left (a x\right )}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*arcsinh(a*x)^(1/2),x, algorithm="maxima")

[Out]

integrate(x*sqrt(arcsinh(a*x)), x)

________________________________________________________________________________________

mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int x\,\sqrt {\mathrm {asinh}\left (a\,x\right )} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*asinh(a*x)^(1/2),x)

[Out]

int(x*asinh(a*x)^(1/2), x)

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x \sqrt {\operatorname {asinh}{\left (a x \right )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*asinh(a*x)**(1/2),x)

[Out]

Integral(x*sqrt(asinh(a*x)), x)

________________________________________________________________________________________